NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2

NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2 are the part of NCERT Solutions for Class 7 Maths (Rationalised Contents). Here you can find the NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2.

NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.1
NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2
NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.3
NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.4
NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.5

NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2 (Rationalised Contents)

Ex 6.2 Class 7 Maths Question 1.

Find the value of the unknown exterior angle x in the following diagrams:

Solution:
(i) ∠x = 70° + 50° = 120°       (Exterior angle is equal to the sum of its opposite interior angles)
(ii) ∠x = 45°+ 65° = 110°        (Exterior angle is equal to the sum of its opposite interior angles)
(iii) ∠x = 40° + 30° = 70°        (Exterior angle is equal to the sum of its opposite interior angles)
(iv) ∠x = 60° + 60° = 120°      (Exterior angle is equal to the sum of its opposite interior angles)
(v) ∠x = 50° + 50° =100°        (Exterior angle is equal to the sum of its opposite interior angles)
(vi) ∠x = 60° + 30° = 90°        (Exterior angle is equal to the sum of its opposite interior angles)

Ex 6.2 Class 7 Maths Question 2.

Find the value of the unknown interior angle x in the following figures:

Solution:
(i) ∠x + 50° = 115°         (Exterior angle of a triangle)
∴ ∠x = 115° – 50° = 65°
(ii) ∠x + 70° = 100°        (Exterior angle of a triangle)
∴ ∠x = 100° – 70° = 30°
(iii) ∠ x + 90° = 125°      (Exterior angle of a right triangle)
∴ ∠x = 125° – 90° = 35°
(iv) ∠x + 60° = 120°       (Exterior angle of a triangle)
∴ ∠x = 120° – 60° = 60°
(v) ∠x + 30° = 80°          (Exterior angle of a triangle)
∴ ∠x = 80° – 30° = 50°
(vi) ∠ x + 35° = 75°        (Exterior angle of a triangle)
∴ ∠ x = 75° – 35° = 40°