- NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.1
- NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2
- NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3
NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2 (Rationalised Contents)
Ex 6.2 Class 6 Maths Question 1.
Using the number line write the integer which is:(a) 3 more than 5
(b) 5 more than -5
(c) 6 less than 2
(d) 3 less than -2
Solution:
(a) 3 more than 5
Moving right 3 steps from 5, we reach at 8. Hence, 3 more than 5 is 8.
(b) 5 more than -5
Moving right 5 steps from -5, we reach at 0. Hence, 5 more than -5 is 0.
(c) 6 less than 2
Moving left 6 steps from 2, we reach at -4. Hence, 6 less than 2 is -4.
(d) 3 less than -2
Moving left 3 steps from -2, we reach at -5. Hence, 3 less than -2 is -5.
Ex 6.2 Class 6 Maths Question 2.
Use number line and add the following integers:(a) 9 + (-6)
(b) 5 + (-11)
(c) (-1) + (-7)
(d) (- 5) + 10
(e) (-1) + (-2) + (-3)
(f) (-2) + 8 + (-4)
Solution:
Ex 6.2 Class 6 Maths Question 3.
Add without using number line:(а) 11 + (-7)
(b) (-13) + (+18)
(c) (-10) + (+19)
(d) (-250) + (+150)
(e) (-380) + (-270)
(f) (-217) + (-100)
Solution:
(a) 11 + (-7) = 4 + (+7) + (-7)
[∵ (+7) + (-7) = 0]
= 4 + 0 = 4
Hence, 11 + (-7) = 4
(b) (-13) + (+18) = (-13) + (+13) + (+5)
[∵ (-13) + (+13) = 0]
= 0 + (+ 5) = 5
Hence, (-13) + (+ 18) = 5
(c) (-10) + (+19) = (-10) + (+10) + (+9)
[∵ (-10) + (10) = 0] = 0 + (+9) = 9
Hence, (-10) + (19) = 9
(d) (-250) + (+150) = (-100) + (-150) + (+150)
= (-100) + 0 = -100 [∵ (-150)
+ (+150) = 0]
Hence, (-250) + (+150) = –100
(e) (-380) + (-270) = – [380 + 270] = (-650)
Hence, (-380) + (-270) = -650
(f) (-217) + (-100) = –[217 + 100] = (-317)
Hence, (-217) + (-100) = -317
Ex 6.2 Class 6 Maths Question 4.
Find the sum of:(a) 137 and -354
(b) -52 and 52
(c) -312, 39 and 192
(d) -50, -200 and 300
Solution:
(a) 137 and -354
(137) + ( -354) = (-217)
(b) -52 and 52
(-52) + (+52) = 0 [ ∵ (-a) + (+ a) = 0]
(c) -312, 39 and 192
(-312) + (+ 39) + (+192)
= (-312) + (231)
= –81
(d) -50, -200 and 300
(-50) + (-200) + (+ 300)
= -(50 + 200) + (+300)
= (-250) + (+300)
= 50
Ex 6.2 Class 6 Maths Question 5.
Find the sum:(a) (-7) + (-9) + 4 + 16
(b) (37) + (-2) + (-65) + (-8)
Solution:
(a) (-7) + (-9) + 4 + 16
= (-7) + (-9) + 4 + (+7) + (+ 9)
= (-7) + (+7) + (-9) + (+9) + 4
= 0 + 0 + 4 = 4 [∵ (-a) + (a) = 0]
(b) (37) + (-2) + (-65) + (-8)
= (+37) + (-75)
= (-38)
Related Links:
NCERT Solutions for Maths Class 7
NCERT Solutions for Maths Class 8
NCERT Solutions for Maths Class 9
NCERT Solutions for Maths Class 10