Maths Quiz for Class 8 Playing with Numbers

Maths Quiz for Class 8 Playing with Numbers

Maths Quiz for Class 8 Playing with Numbers

In this post, we are providing 20 online maths quiz questions for class 8 playing with numbers. Online maths quiz will take around 20 minutes to complete it.

Question 1: If the hundreds, tens and ones digits of a 3-digit number are a, b and c, respectively, then the general form of the 3-digit number is __________.
A) 100c + 10b + a
B) 100b + 10c + a
C) 100a + 10b + c
D) 100c + 10a + b
Explanation: Hundreds digit = a, tens digit = b and ones digit = c. Number = a hundreds + b tens + c ones = a × 100 + b × 10 + c × 1 = 100a + 10b + c
Question 2: If cba is a 3-digit number, the its general form is ____________.
A) 100c + 10b + a
B) 100a + 10b + c
C) 100b + 10c + a
D) 100c + 10a + b
Explanation: The hundreds, tens and ones digits of cba are c, b and c, respectively. Therefore, its general form = c hundreds + b tens + a ones = c × 100 + b × 10 + a × 1 = 100c + 10b + a
Question 3: The difference between any 2-digit number and the number obtained by reversing its digits is always divisible by ________.
A) 9
B) 11
C) 5
D) 7
Explanation: The difference between any two-digit number and the number obtained by reversing its digits is always divisible by 9.
Question 4: The sum of a 2-digit number and the number obtained by reversing its digits will always be divisible by ____________.
A) 9
B) 11
C) 7
D) 13
Explanation: The sum of a 2-digit number and the number obtained by reversing its digits will always be divisible by 11.
Question 5: The difference between any 3-digit number and the number obtained by reversing its digits is always divisible by _________.
A) 13
B) 99
C) 17
D) 91
Explanation: The difference between any 3-digit number and the number obtained by reversing its digits is always divisible by 99.
Question 6: The sum of all the 3-digit numbers formed using the given three digits is always divisible by __________.
A) 39
B) 38
C) 37
D) 35
Explanation: The sum of all the 3-digit numbers formed using the given three digits is always divisible by 37.
Question 7: Which of the following digits cannot be the units digit of a square number?
A) 9
B) 8
C) 6
D) 4
Explanation: 8 cannot be the units digit of a square number.
Question 8: How many zeros can a square number have?
A) 1
B) 3
C) 5
D) 2
Explanation: A square number can have even number of zeros.
Question 9: If 37A + 214 = 5A3, then find the value of A.
A) 9
B) 8
C) 7
D) 6
Explanation: Since 37A + 214 = 5A3, then A + 4 = 3. Take A = 9, then 9 + 4 = 13. Write 3 in ones place and 1 carry over to tens place. Now, 1 + 7 + 1 = 9. Thus, A = 9.
Question 10: If A × A = 2A, then A = _______.
A) 3
B) 4
C) 5
D) 6
Explanation: If we take A = 5, then 5 × 5 = 25. Thus, A = 5.
Question 11: Write 487 in general form.
A) 8 × 100 + 4 × 10 + 7 × 1
B) 4 × 100 + 8 × 10 + 7 × 1
C) 7 × 100 + 8 × 10 + 4 × 1
D) 4 × 100 + 7 × 10 + 8 × 1
Explanation: 487 = 4 × 100 + 8 × 10 + 7 × 1
Question 12: Write 5 × 100 + 2 × 10 + 9 × 1 in numeral form.
A) 592
B) 529
C) 259
D) 925
Explanation: 5 × 100 + 2 × 10 + 9 × 1 = 529
Question 13: Which of the following numbers is divisible by 3?
A) 450921
B) 361270
C) 538024
D) 276103
Explanation: 450921 is divisible by 3, because 4 + 5 + 0 + 9 + 2 + 1 = 21, which is divisible by 3.
Question 14: Check which of the given numbers is divisible by 4 using divisibility test.
A) 507194
B) 248109
C) 375134
D) 910248
Explanation: 910248 is divisible by 4, because the number formed by its last two digits is divisibly by 4.
Question 15: Check which of the given numbers is divisible by 8 using divisibility test.
A) 590164
B) 267306
C) 952072
D) 318642
Explanation: 952072 is divisible by 8, because the number formed by its last three digits is divisibly by 8.
Question 16: Which of the following numbers is not divisible by 5?
A) 487560
B) 384129
C) 387565
D) 162830
Explanation: 384129 is not divisible by 5, because its units digit is 9.
Question 17: Which of the following numbers is divisible by 6?
A) 379104
B) 287650
C) 309621
D) 158426
Explanation: 3 +7 + 9 + 1 + 0 + 4 = 24, which is divisible by 3, so 379104 is divisible by 3. 379104 is divisible by 2 because its units digit is 4. Thus, 379104 is divisible by 6, because it is divisible by 2 and 3 both.
Question 18: Which of the given numbers is divisible by 9?
A) 188409
B) 487605
C) 351063
D) 520178
Explanation: 3 + 5 + 1 + 0 + 6 + 3 = 18, which is divisible by 9. So, 351063 is divisibly by 9.
Question 19: If 57x26 is divisible by 3, then find the smallest value of x.
A) x = 0
B) x = 1
C) x = 2
D) x = 3
Explanation: Since 57x26 is divisible by 3, its sum of digits should also be divisible by 3. Therefore, 5 + 7 + x + 2 + 6 = 20 + x. To make (20 + x) divisibly by 3, we need to take x = 1. Then, 20 + 1 = 21, which is divisible by 3. Thus, the smallest value of x is 1.
Question 20: If 475x09 is divisible by 9, then find the smallest value of x.
A) x = 0
B) x = 1
C) x = 2
D) x = 3
Explanation: Since 475x09 is divisible by 9, its sum of digits should also be divisible by 9. Therefore, 4 + 7 + 5 + x + 0 + 9 = 25 + x. To make (25 + x) divisibly by 9, we need to take x = 2. Then, 25 + 2 = 27, which is divisible by 9. Thus, the smallest value of x is 2.

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